Which will be adsorbed more readily on the surface of charcoal and why: $N H_{3}$ or $C O_{2}$ ?

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Solution

$N H_{3}$ has higher critical temperature than $C O_{2}$ , i.e., $N H_{3}$ is more liquefiable than $C O_{2}$ . Hence, $N H_{3}$ has greater intermolecular forces of attraction and hence will be adsorbed more readily.

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