While measuring the thickness of the glass plate using a screw gauge, the main scale reads 2 mm and head scale coinciding division is 57. If the least count of the screw gauge is 0.01 mm, find out the thickness of glass plate. (Zero error of the screw gauge is zero).

2.57 mm

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6.25 mm

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3.25 mm

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16.3 mm

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Solution

The correct option is A 2.57 mm
Main scale reading $M . S . R . = 2 m m$
Coinciding division $n = 57$
Least count of screw gauge $L . C . = 0.01 m m$
Thickness of wire $t = M . S . R . + n \times L . C . = 2 + 57 \times 0.01 = 2.57 m m$

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While measuring the thickness of the glass plate using a screw gauge, the main scale reads 2 mm and head scale coinciding division is 57. If the least count of the screw gauge is 0.01 mm, find out the thickness of glass plate. (Zero error of the screw gauge is zero).

The correct option is A 2.57 mmMain scale reading M.S.R.=2 mmCoinciding division n=57Least count of screw gauge L.C.=0.01 mmThickness of wire t=M.S.R.+n×L.C.=2+57×0.01=2.57 mm

The correct option is A 2.57 mm
Main scale reading $M . S . R . = 2 m m$
Coinciding division $n = 57$
Least count of screw gauge $L . C . = 0.01 m m$
Thickness of wire $t = M . S . R . + n \times L . C . = 2 + 57 \times 0.01 = 2.57 m m$