CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Without using trigonometric tables, evaluate:
(i) sin50°cos40°+cosec40°sec50°-4 cos52° cosec38°
(ii) cos75°sin15°+sin12°cos78°-cos18° cosec72°
(iii) 2cosec67°sec23°-tan70°cot20°-cos0°+tan38° tan52°
(iv) tan76°cot14°+sec58°cosec32°-sin35° sec55°-8sin230°

Open in App
Solution

(i)sin500cos400+cosec400sec5004cos520cosec380 =sin(900400)cos400+cosec(900500)sec5004cos(900380)cosec380 =cos400cos400+sec500sec5004sin3801sin380 =1+14 =2 (ii)cos750sin150+sin120cos780cos180cosec720 =cos(900150)sin150+sin(900780)cos780cos(900720)cosec720 =sin150sin150+cos780cos780sin720.1sin720 =1+11 =1(iii)2cosec670sec230tan700cot200cos00+tan380tan520 =2cosec(900230)sec230tan(900200)cot2001+tan(900520)tan520 =2sec230sec230cot200cot2001+cot520.1cot520 =211+1 =1(iv)tan760cot140+sec580cosec320sin350sec5508sin2300 =tan(900140)cot140+sec(900320)cosec320sin(900550)sec5508×(12)2 =cot140cot140+cosec320cosec320cos550.1cos5508×14 =1+112=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Ratios
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon