Write a Pythagorean triplet whose one member is
1. $6$
2. $14$
3. $16$

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Solution

$(1.) 6^{2} + 8^{2} = 10^{2} ∴ 6, 8, 10 a r e P y t h a g o r e a n t r i p l e t (2.) 14^{2} + 48^{2} = 50^{2} h e n c e t r i p l e t i s 14, 48, 50 (3.) 16^{2} + 63^{2} = 65^{2} H e n c e t r i p l e t i s 16, 63, 65$

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Write a Pythagorean triplet whose one member is

(i) 6 (ii) 14

(iii) 16 (iv) 18

6

14

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