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Question

Write a pythagorean triplet whose one member is 18.

A
(18,80,82)
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B
(18,82,84)
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C
(18,80,84)
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D
(18,82,86)
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Solution

The correct option is B (18,80,82)
We have pythagorean triplet (2n,n21,n2+1) where n>1 (natural number)
Let n21=18
n2=19
n=19 (not an integer)
n2+1=18
n2=181
n2=17
n=17 (is not an integer)
So, let us take 2n=18
n=9
The required triplet is (an integer)
(18,921,92+1)=(18,811,81+1)
i.e., (18,80,82)

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