Question

Write ${\left(\frac{1}{9}\right)}^{-1/2}\times {\left(64\right)}^{-1/3}$ as a rational number.

Answer 1

$=(\frac{1}{9}{)}^{-\frac{1}{2}}\times (64{)}^{-\frac{1}{3}}$

$=\left(\frac{1}{3}{)}^{2\times \frac{-1}{2}}\right(4{)}^{-3\times \frac{1}{3}}$

$=\left(\frac{1}{3}{)}^{-1}\right(4{)}^{-1}$

$=3\times \frac{1}{4}=\frac{3}{4}$