Question

Write the balanced chemical equations for the following:

1. Monochloroethane is hydrolysed with aqueous KOH.
2. A mixture of sodalime and sodium acetate is heated.
3. Ethanol under high pressure and low temperature is treated with acidified potassium dichromate.
4. Water is added to calcium carbide.
5. Ethanol reacts with sodium at room's temperature.

Answer 1

The chemical reaction as follows:

i. Monochloroethane is hydrolysed with aqueous KOH.

$\underset{\mathrm{chloroethane}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}\left(\mathrm{l}\right)}+\mathrm{KOH}\left(\mathrm{aq}\right)\to \underset{\mathrm{ethanol}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}\left(\mathrm{aq}\right)}+\mathrm{KCl}$

ii. A mixture of sodalime and sodium acetate is heated.

${\mathrm{CH}}_3\mathrm{COONa}+\mathrm{NaOH}\left(\mathrm{aq}\right)\underset{\mathrm{sodalime}}{\overset{\mathrm{CaO}}{\to }}\underset{\mathrm{methane}}{{\mathrm{CH}}_4\left(\mathrm{g}\right)}+{\mathrm{Na}}_2{\mathrm{CO}}_3\left(\mathrm{s}\right)$

iii. Ethanol under high pressure and low temperature is treated with acidified potassium dichromate.

$\underset{\mathrm{ethanol}}{{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\left(\mathrm{aq}\right)}\underset{{\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7}{\overset{\mathrm{acidified}}{\to }}\underset{\mathrm{acetic}\mathrm{acid}}{{\mathrm{CH}}_3\mathrm{COOH}\left(\mathrm{aq}\right)}+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

iv. Water is added to calcium carbide.

$\underset{\mathrm{calcium}\mathrm{carbide}}{{\mathrm{CaC}}_2\left(\mathrm{s}\right)}+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)\to \underset{\mathrm{calcium}\mathrm{hydroxide}}{\mathrm{Ca}{\left(\mathrm{OH}\right)}_2\left(\mathrm{aq}\right)}+{\mathrm{C}}_2{\mathrm{H}}_2\left(\mathrm{g}\right)$

v. Ethanol reacts with sodium at room's temperature.

${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}\left(\mathrm{l}\right)+\mathrm{Na}\left(\mathrm{s}\right)\to \underset{\mathrm{sodium}\mathrm{ethoxide}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{ONa}\left(\mathrm{s}\right)}+\underset{\mathrm{hydrogen}}{\frac{1}{2}{\mathrm{H}}_2\left(\mathrm{g}\right)}$