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Question

# Write the balanced equation for the following reaction: Sodium hydroxide reacts with calcium bromide to form calcium hydroxide and sodium bromide.

A

2NaOH+CaBr2Ca(OH)2+2NaBr

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B

NaOH+CaBr2Ca(OH)2+NaBr

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C

NaOH+CaBrCa(OH)2+2NaBr

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D

2NaOH+CaBr2Ca(OH)2+NaBr2

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Solution

## The correct option is A 2NaOH+CaBr2→Ca(OH)2+2NaBr The chemical equation for the following reaction will be: Sodium hydroxide + Calcium bromide ⟶ Calcium hydroxide + Sodium bromide. Sodium hydroxide - NaOH, Calcium bromide - CaBr2, Calcium hydroxide - Ca(OH)2, Sodium bromide - NaBr So the equation will be written as: NaOH+CaBr2→Ca(OH)2+NaBr Now to balance the equation we have to count the number of atoms on each side. Number of Oxygen atoms on LHS - 1, Number of Oxygen atoms on RHS - 2 So we will multiply 2 on the reactant side to NaOH. So it will become; 2NaOH+CaBr2→Ca(OH)2+NaBr Number of Na atoms on the reactant side: 2; Number of Na atoms on the product side: 1 So we will multiply 2 on the product side to NaBr. So it will become; 2NaOH+CaBr2→Ca(OH)2+2NaBr Number of Hydrogen atoms on LHS - 2, Number of Hydrogen atoms on RHS - 2 Number of Calcium atoms on LHS - 1, Number of Calcium atoms on RHS - 1 Number of Bromine atoms on LHS - 2, Number of Bromine atoms on RHS - 2 Hence the equation is balanced. 2NaOH+CaBr2→Ca(OH)2+2NaBr

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