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Reaction of Acids with Metal Carbonates and Bicarbonates

Write the bal...

Question

Write the balanced equation for the laboratory preparation of sodium sulphate using dilute sulphuric acid.

{N a}_{2} {S O}_{3} + H_{2} {S O}_{4} (d i l) \to {N a}_{2} {S O}_{4} + H_{2} O + {S O}_{2}

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2 {N a}_{2} {S O}_{3} + H_{2} {S O}_{4} (d i l) \to 2 {N a}_{2} {S O}_{4} + H_{2} O + {S O}_{2}

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{N a}_{2} {S O}_{3} + 3 H_{2} {S O}_{4} (d i l) \to {N a}_{2} {S O}_{4} + 3 H_{2} O + {S O}_{2}

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{N a}_{2} {S O}_{3} + 2 H_{2} {S O}_{4} (d i l) \to 2 {N a}_{2} {S O}_{4} + H_{2} O + {S O}_{2}

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Solution

The correct option is A ${N a}_{2} {S O}_{3} + H_{2} {S O}_{4} (d i l) \to {N a}_{2} {S O}_{4} + H_{2} O + {S O}_{2}$
In the laboratory, sodium sulphite reacts with diluted sulfuric acid and forms sodium sulphate.

The balanced chemical equation is $N a_{2} S O_{3} + H_{2} S O_{4} (d i l) \to N a_{2} S O_{4} + H_{2} O + S O_{2}$ .

So the correct option is A.

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Similar questions

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

S + O_{2} \to {S O}_{2}; Δ H = - 298.2 k J

{S O}_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

H_{2} {S O}_{4}

S + O_{2} \to {S O}_{2}; △ H = - 298.2 k J

{S 0}_{2} + 1 / 20_{2} \to {S O}_{3}; △ H = - 98.7 k J

S O_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J

H_{2} + 1 / 20_{2} \to H_{2} O; △ H = - 287 k J

H_{2} {S O}_{4}

S + O_{2} \to {S O}_{2}; △ H = - 398.2 k J : {S O}_{2} + \frac{1}{2} O_{2} \to {S O}_{3}; △ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J : H_{2} + \frac{1}{2} O_{2} \to H_{2} O, △ H = - 227.3 k J

H_{2} {S O}_{4}

(a) H_{2} {S O}_{4} + N a O H \to N a H {S O}_{4} + H_{2} O

(b) H_{2} {S O}_{4} + 2 N a O H \to {N a}_{2} {S O}_{4} + 2 H_{2} O

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