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Question

Write the distance between the lines 4x+3y11=0 and  8x+6y15=0.


Solution

Let (h,k) be the point on the line

4x+3y11=0

4h+3k11=0          ...(1)

Distance of (h,k) from line 8x+6y15=0

D=|ax1+by1+c|a2+b2

=|8h+6k15|64+36

=|2(11)15|10                [Using(1)]

D=710units.

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