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Question

Write the equations involved in the preparation of potassium dichromate from sodium chromate ($$Na_{2}CrO_{4}$$).


Solution

Sodium chromate is acidified with sulphuric acid to give a solution from which orange sodium dichromate, $$Na_{2}Cr_{2}O_{7}.2H_{2}O$$ can be crystallised.
$$2Na_{2}CrO_{4} + 2H^{+} \rightarrow Na_{2}Cr_{2}O_{7} + 2Na^{+} + H_{2}O$$
Sodium dichromate is more soluble than potassium dichromate. The latter is therefore prepared by treating the solution of sodium dichromate with potassium chloride.
$$Na_{2}Cr_{2}O_{7} + 2KCl \rightarrow K_{2}Cr_{2}O_{7} + 2NaCl$$

Chemistry

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