    Question

# Write the following equation in ionic form:a) MnO2+4HCl→MnCl2+2H2O+Cl2b) 2NaHCO3+H2SO4→Na2SO4+H2O+CO2

A
a) MnO2+4H++4ClMn2++2Cl+2H2O+Cl2,
b) 2Na++2HCO3+2H++SO242Na++SO24+2H2O+CO2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a) 2MnO2+8H++4Cl2Mn2++2Cl+4H2O+Cl2,

b) 2Na++2HCO3+2H++SO242Na++SO24+2H2O+CO2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a) MnO2+4H++3ClMn2++Cl+2H2O+Cl2,
b) 2Na++2HCO3+2H++SO242Na++SO24+2H2O+CO2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C a) MnO2+4H++4Cl−→Mn2++2Cl−+2H2O+Cl2, b) 2Na++2HCO−3+2H++SO2−4→2Na++SO2−4+2H2O+CO2(a) In the first reaction, MnCl2 and HCl are ionic in nature. Therefore, the reaction in ionic form is as follows:∴MnO2+4H++4Cl−→Mn2++2Cl−+2H2O+Cl2 (Taking 2Cl− common)(b) In the second reaction, NaHCO3,H2SO4 and Na2SO4 are ionic in nature.Therefore, the reaction in ionic form is as follows:2Na++2HCO−3+2H++SO2−4→2Na++SO2−4+2H2O+CO2 (Taking SO2−4 common) or 2Na++2HCO−3+2H++SO2−4→2Na++2H2O+CO2.  Suggest Corrections  0      Similar questions  Related Videos   Equivalent, Molar Conductivity and Cell Constant
CHEMISTRY
Watch in App  Explore more