Question

Write the following equation in ionic form.
$Mn{O}_2+4HCl\to MnC{l}_2+2H_{2}O+C{l}_2$.

Answer 1

In the given equation $HCl$ and $MnC{l}_2$ are ionic in nature while $Mn{O}_2$ $H_{2}O$ and $C{l}_2$ are non ionic nature. So the compounds with ionic nature will be written as
$Mn{O}_2+4H^{+}+4C{l}^{-}=M{n}^{2+}+2C{l}^{-}+2H_{2}O+C{l}_2$.
$2C{l}^{-}$ ions are common on both sides; so these are cancelled. The desired ionic equation reduces to,
$Mn{O}_2+4H^{+}+2C{l}^{-}=M{n}^{2+}+2H_{2}O+C{l}_2$.