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Question

Write the sum of geometrical isomers in [Pt(H$$_2$$N - CH(CH$$_3$$) - COO$$^-$$)$$_2$$] complex and stereoisomers of [Pt(gly)$$_3$$]$$^+$$ complex.


Solution

Total number of geometrical isomers in [Pt(H$$_2$$N - CH(CH$$_3$$) - COO$$^-$$)$$_2$$] = 4
Total number of stereo isomers in [Pt(gly)$$_3$$]$$^+$$ = 4
Sum of geometrical isomers and stereo isomers of given complexes = 8
Thus, the sum of geometrical isomers in [Pt(H$$_2$$N - CH(CH$$_3$$) - COO$$^-$$)$$_2$$] complex and stereoisomers of [Pt(gly)$$_3$$]$$^+$$ complex is 8.

Chemistry

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