Write the sum of geometrical isomers in [Pt(H $_{2}$ N - CH(CH $_{3}$ ) - COO $^{-}$ ) $_{2}$ ] complex and stereoisomers of [Pt(gly) $_{3}$ ] $^{+}$ complex.

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Solution

Total number of geometrical isomers in [Pt(H $_{2}$ N - CH(CH $_{3}$ ) - COO $^{-}$ ) $_{2}$ ] = 4
Total number of stereo isomers in [Pt(gly) $_{3}$ ] $^{+}$ = 4
Sum of geometrical isomers and stereo isomers of given complexes = 8
Thus, the sum of geometrical isomers in [Pt(H $_{2}$ N - CH(CH $_{3}$ ) - COO $^{-}$ ) $_{2}$ ] complex and stereoisomers of [Pt(gly) $_{3}$ ] $^{+}$ complex is 8.

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