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Question

Write the value of 2(sinθ+cos6θ)3(sin4θ+cos4θ)+1.


Solution

2(sin6θ+cos6θ)3(sin4θ+cos4θ)+1

=2((sin3θ)2+(cos3θ)2)3((sin2θ)2)+(cos2θ)2)+1

=2(1)-3(1)+1

=2-3+1

=0

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