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Question 11.
(x2+1)2x2 = 0 has:

(a) four real roots

(b) two real roots

(c) no real roots

(d) one real roots


Solution

Option (C)
Given,  (x2+1)2x2 = 0
(x2+1)2=x2
Square root on both sides. We get,
x2+1=x   or   x2+1=x
x2x+1=0   or   x2+x+1=0
discriminant for the above equations will be;
 1-4 = -3  <0   or  1-4=-3 <0
Hence, (x2+1)2x2 = 0 has no real roots.


Mathematics

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