x+2 is a factor of $x^{3} + 8$

True

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False

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Solution

The correct option is A
True

If remainder of $\frac{p (x)}{(x - a)}$ is 0, x - a is a factor of p(x)

P(-2) = $(- 2)^{3}$ + 8 = 0

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Similar questions

Q. Using factor theorem, show that g(x) is a factor of p(x), when
p(x) = x³ – 8, g(x) = x – 2

Q. For the equation

x^{3} + 11 x^{2} + 22 x + 8 = 0

x + 2

is a factor.

Q. Using factor theorem, show that:
(x − 2) is a factor of (x³ − 8)

Q. Find the value of

k

, if

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is a factor of polynomial

p (x) = x^{3} + k x^{2} + 12 x - 8

$(x + 1)$ is a factor of the polynomial
(a) $x^{3} - 2 x^{2} + x + 2$ (b) $x^{3} + 2 x^{2} + x - 2$
(c) $x^{3} + 2 x^{2} - x - 2$ (d) $x^{3} + 2 x^{2} - x + 2$

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x+2 is a factor of x3+8

The correct option is A True If remainder of p(x)(x−a) is 0, x - a is a factor of p(x) P(-2) = (−2)3 + 8 = 0

x+2 is a factor of $x^{3} + 8$

The correct option is A
True

If remainder of $\frac{p (x)}{(x - a)}$ is 0, x - a is a factor of p(x)

P(-2) = $(- 2)^{3}$ + 8 = 0