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Question

x4(xz)4=


  1. z(2x+z)(2x22xz+z2)

  2. z(2x+z)(2x2+2xz+z2)

  3. z(2xz)(2x22xz+z2)

  4. z(2xz)(2x2+2xz+z2)


Solution

The correct option is C

z(2xz)(2x22xz+z2)


x4(xz)4=(x2)2[((xz)2)2]=[x2(xz)2][x2+(xz)2]=[x(xz)][x+(xz)][x2+(xz)2]=z(2xz)[x2+x22xz+z2]=z(2xz)(2x22xz+z2)

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