Question

X and Y are two volatile liquids with molar weights of 10 gmol−1and 40 gmol−1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

The value of d in cm (shown in the figure as estimated from Graham’s law, is

- 8
- 12
- 16
- 20

Solution

The correct option is **C** 16

Remember

vx/vy=√(My/Mx)=√(4/1)

So the velocities are in the ratio 2:1.

Since the time taken must be the same for both the gases, the distance travelled will be in the ratio 2:1. We divide the tube into 3 parts, each part has a length of 8 cm. Hence, the distance d = 16 cm (because of the ratio of distances/velocites being 2:1).

Remember

vx/vy=√(My/Mx)=√(4/1)

So the velocities are in the ratio 2:1.

Since the time taken must be the same for both the gases, the distance travelled will be in the ratio 2:1. We divide the tube into 3 parts, each part has a length of 8 cm. Hence, the distance d = 16 cm (because of the ratio of distances/velocites being 2:1).

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