Question

'x' moles of $N_2$ gas at S.T.P conditions occupy a volume of 10 litres, then the volume of '2x' moles of $C{H}_4$ at ${273}^{0}C$ and 1.5 atm is

• A. 20 lit
• B. 26.6 lit
• C. 5 lit
• D. 16.6 lit

Answer 1

The correct option is B

26.6 lit

$\frac{P_1{V}_1}{n_1{T}_1}=\frac{P_2{V}_2}{n_2{T}_2}$

$\frac{1\times 10}{n\times 273}=\frac{1.5\times V_2}{2x\times 546}$

$V_2=26.6lit$