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Question

xx has a stationary point at
[Karnataka CET 1993]

  1. x = e
  2. x=1e
  3. x=e
  4. x = 1 


Solution

The correct option is B x=1e
tan u=x+y=x(1+yx)

 tan u is homogeneous in x,y of order 1.
 xy(tan u)=tan u
 sec2 ux+y sec2 uuy=tan u
 x ux+y yuy=tan u.cos2u=sin u cos u=12 sin2u.

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