Question

Xenon fluorides and oxyfluorides undergo hydrolysis. Match the following reactions with their products:

• A. ${\mathrm{XeOF}}_4+2\mathrm{HF}$
• B. $2\mathrm{Xe}+O_2+4\mathrm{HF}$
• C. ${\mathrm{XeO}}_3+4\mathrm{HF}$
• D. ${\mathrm{XeO}}_3+6\mathrm{HF}$

Answer 1

$2{\mathrm{XeF}}_2+2H_{2}0\to 2\mathrm{Xe}+O_2+4\mathrm{HF}$$6{\mathrm{XeF}}_4+12H_{2}O\to 4\mathrm{Xe}+3O_2+2{\mathrm{XeO}}_3+24\mathrm{HF}$${\mathrm{XeF}}_6+3H_{2}O\to {\mathrm{XeO}}_3+6\mathrm{HF}$

Partial hydrolysis of XeF₆ gives oxyfluorides:
${\mathrm{XeF}}_6+H_{2}O\to {\mathrm{XeOF}}_4+2\mathrm{HF}$
${\mathrm{XeF}}_6+2H_{2}O\to {\mathrm{XeO}}_2{F}_2+4\mathrm{HF}$

${\mathrm{XeOF}}_4+2H_{2}O\to {\mathrm{XeO}}_3+4\mathrm{HF}$