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Question

Question 88 (xiv)

Factorise the following expression.

2x22y+4xyx


Solution

We have, 2x22y+4xyx
=2x2x2y+4xy=x(2x1)2y(12x)
=x(2x1)+2y(2x1)=(2x1)(x+2y)

Mathematics
NCERT Exemplar
Standard VIII

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