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Multiplication of Any Polynomial

xv Multiply t...

Question

Question 83 (xv)

Multiply the following:
$(a^{2} - b^{2}), (a^{2} + b^{2})$

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Solution

We have, $(a^{2} - b^{2}) a n d (a^{2} + b^{2})$
$∴ (a^{2} - b^{2}) (a^{2} + b^{2})$ = $a^{2} (a^{2} + b^{2}) - b^{2} (a^{2} + b^{2})$
$= a^{4} + a^{2} b^{2} - b^{2} a^{2} - b^{2} = a^{4} - b^{4}$

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Similar questions

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

Q. Question 4
If

s i n θ = \frac{a}{b}

c o s θ

is equal to

(A)

\frac{b}{\sqrt{b^{2} - a^{2}}}

\frac{b}{a}

\frac{\sqrt{b^{2} - a^{2}}}{b}

\frac{a}{\sqrt{b^{2} - a^{2}}}

Q. Question 90 (vii)

Factorise the following, using the identity,

a^{2} - 2 a b + b^{2} = (a - b)^{2}

a^{2} y^{2} - 2 a b y + b^{2}

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}}

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Multiplication of Any Polynomial

Standard VIII Mathematics

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