Question

# Yellow light emitted from a sodium lamp has a wavelength $$(\lambda)$$ of 580 nm. Calculate the frequency $$(\nu)$$, wave number and energy of yellow light photon.

Solution

## Frequency $$(\nu)= \dfrac {c}{\lambda}=\dfrac {3.0 \times 10^8}{580 \times 10^{-9}}=5.17 \times 10^{14}$$ Hz Wave number $$={\overline \nu}= \dfrac {1}{\lambda}=\dfrac {1}{580 \times 10^{-9}}=1.724 \times 10^{6} m^{-1}$$Energy, $$E=h{\nu}= 6.626 \times 10^{-34} \times 5.17 \times 10^{14}$$                  $$=34.25 \times 10^{-20}$$ J/photonChemistry

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