You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of :

(a) potassium chloride (b) potassium nitride

(c) potassium sulphide (d) potassium iodide

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Solution

When potassium iodide is added to a solution of lead nitrate then a yellow precipitate is formed.

$2 K I + P b (N O_{3}) ⟶ P b I_{2} + 2 K N O_{3}$
Potassium Lead Lead Potassium
Iodide Nitrate Iodide Nitrate

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Similar questions

Q. You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of:
(a) potassium chloride
(b) potassium nitride
(c) potassium sulphide
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You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of : (a) potassium chloride (b) potassium nitride (c) potassium sulphide (d) potassium iodide

When potassium iodide is added to a solution of lead nitrate then a yellow precipitate is formed. 2KI + Pb(NO3)⟶PbI2+2KNO3 Potassium Lead Lead Potassium Iodide Nitrate Iodide Nitrate

You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of :

(a) potassium chloride (b) potassium nitride

(c) potassium sulphide (d) potassium iodide

When potassium iodide is added to a solution of lead nitrate then a yellow precipitate is formed.

$2 K I + P b (N O_{3}) ⟶ P b I_{2} + 2 K N O_{3}$
Potassium Lead Lead Potassium
Iodide Nitrate Iodide Nitrate