1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Young’s double slit experiment is carried with two thin sheets of thickness 10.4μ m each and refractive index μ1=1.52 and μ2=1.40 covering the slits S1 and S2, respectively, If white light of range 400 nm to 780 nm is used, then which wavelength will form maxima exactly at point O, the centre of the screen?

A
416 nm only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
624 nm only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both 416 nm and 624 nm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Both 416 nm and 624 nm Path difference = (μ1−μ2)t=12480˙A For maxima, nλ=12480˙A λ1=12480˙A, λ2=6240˙A λ3=4160˙A, λ4=3120˙A Therefore, both 6240˙A and 4160˙A exist in the spectrum.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Optical Path
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program