Zinc reacts with hot and concentrated NaOH and forms:

Z n (O H)_{2} + N a_{2} O

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Z n O

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O_{2}

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H_{2}

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Solution

The correct option is D $H_{2}$
Zinc reacts with hot and concentrated NaOH and forms $H_{2}$ .

$Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$

Hence, option $D$ is correct.

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