1 mole atom of diatomic gas at NTP will be 11.2 litres

We know that, 1 mole of gas occupies 22.4 L at NTP 1 mole of O2 gas occupies 22.4 L at NTP O2 contains 2 moles of oxygen atom. Hence 2 moles of oxygen atom occupies 22.4 L at NTP Mole = Volume / 22.4 Therefore, 1 mole of oxygen atom contains 22.4 / 2 = 11.2 L at NTP.

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