10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be (a) 4 mL (b) 8 mL (c) 12 mL (d) 16 mL

Answer: (d) 16 mL

Since 10 ml of NaOH requires 8 mL of HCl.

20 ml of NaOH require_______HCl.

Let X be the amount of HCl required to neutralize the 20 ml of NaOH.

X = (20 × 8)/10

X = 16 ml

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