1000 w heater is used 6 hours daily and the cost of 1 unit of electricity is 40 p. how much will it cost in the month of november?

Solution:

Here P = 1000

t = 6 × 30 = 180 hours

Energy consumed \(=frac{Ptimes t}{1000}\) \(=frac{1000times 180}{1000}\)

= 180 kWh

Cost \(=frac{180times 40}{100}=Rs.72\)