Solution:
Here P = 1000
t = 6 × 30 = 180 hours
Energy consumed
\(\begin{array}{l}=frac{Ptimes t}{1000}\end{array} \)
\(\begin{array}{l}=frac{1000times 180}{1000}\end{array} \)
= 180 kWh
Cost
\(\begin{array}{l}=frac{180times 40}{100}=Rs.72\end{array} \)
