1000 w heater is used 6 hours daily and the cost of 1 unit of electricity is 40 p. how much will it cost in the month of november?

Solution:

Here P = 1000

t = 6 × 30 = 180 hours

Energy consumed

\(\begin{array}{l}=frac{Ptimes t}{1000}\end{array} \)
\(\begin{array}{l}=frac{1000times 180}{1000}\end{array} \)

= 180 kWh

Cost

\(\begin{array}{l}=frac{180times 40}{100}=Rs.72\end{array} \)

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