2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.

Ncert solutions class 10 chapter 13-1

Volume of cube=64cm= (side)3

(Side)= 64

Side = (64cm31/3

= (2*2*2*2*2*2 cm3)1/3 

= 2*2

= 4 cm

Hence, 

Length = 8 cm

breadth = 4 cm

Height = 4 cm

Surface area of cuboid=2(lb+bh+hl)

=2(8*4+4*4+4*8)

=2(32+16+32)

=2(80)

=160cm2

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