20 ml of 0.2M Al2(SO4)3 is mixed with 20ml of 6.6 M BaCl2 , the concertration of Cl - ion in solution is: 1) 0.2 2) 6.6 3) 0.02 4) 0.06

Answer: (2) 6.6 M

20mL of 0.2M Al2(SO4)3 is mixed with 20mL of 6.6M BaCl2

Concentration of Cl = (Total amount of Chlorine)/Total volume

Total amount of chloride ion in solution = 2 × 20(ml) × 6.6(mmol/ml) = 264 m mol

Total volume = 20 + 20 = 40 mL

Concentration of Cl ion = 264/40 = 6.6M

Was this answer helpful?

  
   

0 (0)

Upvote (1)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question