(2-7x)/(1-5x)=(3+7x)/(4+5x). Solve for x.

(2-7x)/(1-5x)=(3+7x)/(4+5x)

By applying alternendo,

\(\frac{2-7 x}{3+7 x}=\frac{1-5 x}{4+5 x}\)

Now applying Componendo and Dividendo,

\(\begin{array}{l} \frac{(2-7 x)+(3+7 x)}{(2-7 x)-(3+7 x)}=\frac{(1-5 x)+(4+5 x)}{(1-5 x)-(4+5 x)} \\ \frac{5}{-1-14 x}=\frac{5}{-3-10 x} \end{array}\)

−1−14x=−3−10x

14x−10x=3−1

4x=2

x=1/2

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