3 (t – 3) = 5 (2t – 1)
By removing brackets
=3t – 9 = 10t – 5
By transposing 9 to RHS and 10t to LHS we get
= 3t – 10t – 9 = 5
= -7t – 9 = 5
= – 7t = 14
= t =
\(\begin{array}{l} frac{14}{-7}\end{array} \)
= t = -2
Therefore, the equation is solved
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