Solution
Let the length of the ladder = AC = 5 m
Let the height of the wall on which ladder is placed = BC = 4m.
From right-angled ∆EBD,
On applying the Pythagoras Theorem,
ED2 = EB2 + BD2
(5)2 = (EB)2 + (14)2 [ BD = 1.4]
25 = (EB)2 + 1.96
(EB)2 = 25 –1.96 = 23.04
EB = √23.04 = 4.8
Now, we have,
EC = EB – BC = 4.8 – 4 = 0.8
Answer
Hence, the top of the ladder would slide upwards on the wall by a distance of 0.8 m.