# A 6-ohm resistance wire is doubled by folding. What is the new resistance?

The electrical resistance of a circuit is the ratio between the voltage applied to the current flowing through it.

According to Ohm’s law, there is a relation between the current flowing through a conductor and the potential difference across it. It is given by,

I V = IR

Where,
• V = Potential difference measured across the conductor (in volts)
• I = Current through the conductor (in amperes)
• R = Constant of proportionality called resistance (in ohms)

### Given

R = 6 Ohms

$$\begin{array}{l}R = \frac{\rho l}{A}\end{array}$$
————-(1)

Wire is doubled so,

• Area (A) = 2A
• length (l) = l/2

New Resistance will be:

$$\begin{array}{l}R_{new} = \frac{\rho (\frac{l}{2})}{2A}\end{array}$$

Rnew = ρl/4A

By using eqaution (1) we can simplify the above equation as

Rnew = R/4

Rnew = 6/4

Rnew = 1.5 Ohms

Hence, the new Resistance of wire is 1.5 Ohms.

For additional information on resistance and Ohm’s Law, refer to the video