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Question

An 8000kg engine pulls a train of 5 wagons, each of 2000kg, along a horizontal track. If the engine exerts a force of 40000N and the track offers a friction force of 5000N, then calculate: (a) the net accelerating force (b) the acceleration of the train (c)the force of wagon 1 on wagon 2.


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Solution

Step 1: Given Data

The mass of the engine M=8000kg

Total number of wagons n=5

Mass of each wagon m=2000kg

Force exerted by the engine F=40000N

The frictional force of the tracks f=5000N

Step 2: Calculate the net force

Therefore the net accelerating force on the train can be given as

Fnet=F-f

=40000-5000

=35000N

Step 3: Acceleration of the train

The total mass of the train can be given as

mt=M+nm

=8000+5×2000

=18000kg

Let the acceleration of the train be a.

The net force can be given as

Fnet=mta

a=Fnetmt

a=3500018000

a=1.944m/s2

Step 4: Force applied between wagon 1 & 2

The force applied to wagon 2 by wagon 1 can be given as

F21=4ma

=4×2000kg×1.944ms2

=15552N

Hence, (a) the net accelerating force is 35000N (b) the acceleration of the train is 1.944m/s2 (c) the force of wagon 1 on wagon 2 is 15552N.


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