A bag contains 25 paise coins, 50 paise coins and 1 rupee coins whoose values are in the ratio of 8:4:2. the total values of coins are 840. Then find the total number of coins.

Given

In a bag 25 paise coins, 50 paise coins, and 1 rupee coins whose values are in the ratio of 8:4:2. the total values of coins are 840.

We need to find the total number of coins.

Solution

Let us assume that

Number of 25p coins = 8x

Number of 50p coins = 4x

Number of Rs. 1 coins = 2x

As per the given condition

8x + 4x + 2x = 840

14x = 840

x = 840/14

x = 60

Hence,

Amount of 25p coin = 60 × 8 × 25 = 12000 paisa = Rs. 120

Amount of 50p coin = 60 × 4 × 50 = 12000 paisa = Rs. 120

Amount of Rs. 1 coin = 60 × 2 × 1 = Rs. 120

On summing up the above-obtained values the total amount in the bag is Rs120+Rs120 +Rs 120 = Rs360

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