A ball is dropped from a height of 10 m. If the energy of the ball reduces by 40% after striking the ground, how much high can the ball bounce back? (g = 10 m s–2) .

Answer: Height at which the ball will bounce back is 6 meters

Given parameters

Ball dropped at the height (h) = 10 m

g = 10ms-2

Total energy of the ball = m × g× h

Total energy of the ball = m × 10 × 10

Total energy of the ball = 100 mJ

The ball loses 40 percent of its initial energy on striking the ground level

⇒ (40/100) × 100 mJ

The ball loses 40 percent of its initial energy on striking the ground level = 40 mJ

Energy left to hit the ground = 100 m J – 40 m J

Energy left to hit the ground = 60 mJ

∴ Final energy of the ball = 60 mJ

Height at which the ball will bounce back

H = 60/10

H = 6m

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