CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball is dropped from a height of 10m. If the energy of the ball reduces by 40% after striking the ground, how high can the ball bounce back? (g=10ms-2) .


Open in App
Solution

Step 1: Given Data

Initial height from where the ball is dropped h=10m

Acceleration due to gravity g=10ms-2

The energy of the ball reduced =40%

Let m be the mass of the ball.

Let the height of the ball after rebound be h'.

Step 2: Calculate the total potential energy

We know that the initial potential energy of the ball is

PE=mgh

=m×10×10

=100m

Step 3: Calculate the reduced potential energy

Since 100m is the total energy, then the reduced energy can be given as

=100m-40%of100m=100m-40100×100m=100m-40m=60m

Step 4: Calculate the bounced height

This is the energy of the ball when it bounces back.

60m=mgh'

h'=60g

h'=6010=6m

Hence, the ball can bounce back 6m high.


flag
Suggest Corrections
thumbs-up
73
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Realistic Collisions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon