# A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in an equilibrium state. The energy required to rotate it by 60° is W. Now the torque required to keep the magnet in this new position isa) $\frac{W}{\sqrt{3}}$b) $\frac{\sqrt{3}}{2}W$c) $\sqrt{3}W$d) $\frac{2W}{\sqrt{3}}$

Option c) $\sqrt{3}W$.