A bar magnet is oscillating in the earths magnetic field with a period T. What happens to its period and motion if its mass is quadrupled? A. Motion remains S.H.M. with time period =2T B. Motion remains S.H.M. with time period =4T C. Motion remains S.H.M. and period remains nearly constant D. Motion remains S.H.M. with time period = T/2

Answer: A. Motion remains S.H.M. with time period =2T

T = 2π√(I/MB)

where ‘I’ is the moment of inertia

∵I ∝ m, where m is the mass

So, T ∝ √m

Thus,

T1/T2 = √m1/√m2

Since, initial mass of magnet, m1 = m and final mass, m2 = 4m. Therefore,

T1/T2 = √m/√4m = 1/2

T2 = 2T1 = 2T

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