A Billiard Ball Moving With A Speed Of 5M/S Collides With An Identical Ball Originally At Rest. If The First Ball Stops After Collision, Then The Second Ball Will Move Forward With A Speed

Since There is no external force, we can apply momentum conservation,

\( P_{1} = m(V) = 5m \) \( P_{2} = 0 \) \( P_{i} = 5m + 0 = 5m \) \( P_{f} = m * 0 + mv_{2} \) \( P_{i} = P_{f} \) \( 5m = mv_{2} \) \( v_{2} = 5m/s \)

Due to the elastic collision of bodies having equal mass, their velocities get interchanged.

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question