A body initially at rest and sliding along a frictionless track from a height h just completes a vertical circle of diameter AB=D. What is the height h equal to?

Let total energy be conserved.

Total mechanical energy at start = total mechanical energy at B

mgh = \(frac{1}{2}mv_{B}^{2}\) +mgD

The minimum speed required to complete rotation is 

vb=√rg=√Dg/2

Therefore,

mgh=1/2mD/2g+mgD

Hence,

h=5D/4

image pending

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