# A Body Is Projected Along A Rough Horizontal Surface With A Velocity Of 6 m/s. If The Body Comes To Rest After Travelling A Distance Of 9 M, The Coefficient Of Sliding Friction Is (g=10ms−2).

Friction acts as deceleration force on the body,

ma = μmg

a = μmg

Distance travelled before coming to rest = 9 m.

$$v^{2} – u^{2} = 2as$$ $$\Rightarrow 0 – 6^{2} = -2(\mu g)(9)\\\Rightarrow \frac{36}{2 * 10 * 9}\\\Rightarrow 0.2$$.

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