A Body Moves 6 M North 8 M East And 10M Vertically Upwards What Is Its Resultant Displacement From Initial Position (Only Magnitude)

Let us consider

East direction to be x-direction

North direction to be y-direction

vertically upward direction to be z-direction

Displacement of the particle is given by

\(vec{s}=8hat{i}+6hat{j}+10hat{k}\)

Magnitude of displacement

\( left | vec{S} right |=sqrt6^{2}+{8^{2}}+{10^{2}} \)

Therefore, the resultant displacement from the initial position (only magnitude) is

\( left | vec{S} right |=10sqrt2m \)

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