Question

A rectangular body of dimensions ( $l\times b\times h$ ) $2m\times 3m\times 4m$ is acted upon by a force of $50N$on the top surface. Calculate the pressure due to the force on that surface.

Answer 1

Step1: Given data

A body of dimensions ( $l\times b\times h$ ) is $2m\times 3m\times 4m$.

Force, $f=50N$

Step2: Formula used

The pressure is defined as the force per unit area which is perpendicular to the surface. The S.I. unit of pressure is Pascal (Pa).

$P=\frac{F}{A}[whereP=pressure,F=force,A=area]$

Step3: Calculating pressure

$$\begin{gathered} Areaofrec\tan gle=l\times b \\ A=2m\times 3m \\ A=6m^2 \end{gathered}$$

Substituting the given value of force and area in the pressure formula

$$\begin{gathered} P=\frac{F}{A} \\ P=\frac{50}{6} \\ P=8.34Pa \end{gathered}$$

Hence, the pressure due to the force on that surface will be $8.34Pa$.