CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass m hits normally a rigid wall with velocity v and bounces back with the same velocity. The impulse experienced by the body is


A

1.5mv

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2mv

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

1mv

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

2mv


Step1: Impulse

  1. When a large amount of force is exerted on a body in a very small time, then the force is called impulse.
  2. Impulse is defined as the change in momentum in a small-time, i.e, impulse, p=pf-pi.

Step2: Finding the impulse

The momentum of the body, when it hits the wall is

pi=+mv

The momentum of the body, when it is bounced back is

pf=-mv

Now change in momentum,

p=-mv-mv

or p=-2mv

The impulse experienced by the body is p=-2mv. So Option (B) is correct.


flag
Suggest Corrections
thumbs-up
16
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Momentum Returns
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon