A Bulb Emits Light Of Wavelength Λ=4500 A˚. The Bulb Is Rated As 150 Watt And 8% Of The Energy Is Emitted As Light. How Many Photons Are Emitted By The Bulb Per Second?

Energy emitted by the bulb per second = \( 150 * \frac{8}{100}J\)

As the energy of 1 photon = \( \frac{hc}{\lambda}\)

= \( \frac{6.626 * 10^{-34} * 3 * 10^{8}}{4500*10^{-10}}\)

= \( 4.42 * 10^{-19} joule\)

Let the photons emitted by the bulb per second be x

= \( n * 4.42 * 10^{-19}\)

= \( 150 * \frac{8}{100}\)

= n = \( 27.2 * 10^{18}\)

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