A bus starting from rest moves with a uniform acceleration of 0.1 ms-2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Given

The bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes

Find out

Acceleration and distance travelled

Solution

(a) Acceleration

The bus starts from rest.

Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s-2

Time = 2 minutes = 120 s

Acceleration is given by the equation a=(v-u)/t

Therefore, terminal velocity (v) = (at)+u

= (0.1 m.s-2 * 120s) + 0 m.s-1

= 12m.s-1 + 0 m.s-1

Therefore, terminal velocity (v) = 12m/s

(b) As per the third motion equation,

Since a = 0.1 m.s-2, v = 12 m.s-1, u = 0 m.s-1, and t = 120s, the following value for s (distance) can be obtained.

Distance, s =(v2 – u2)/2a

=(122 – 02)/2(0.1)

Therefore, s = 720m.

The speed acquired is 12m.s-1 and the total distance traveled is 720m.

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